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3211130022221 = 11808736097553
BaseRepresentation
bin101110101110100110010…
…000111010100101001101
3102100222111011122200010202
4232232212100322211031
5410102343241202341
610455101152343245
7450665536556342
oct56564620724515
912328434580122
103211130022221
111028918202350
1243a408b44b25
131a3a6799c334
14b15c32527c9
15587ded8c79b
hex2eba643a94d

3211130022221 has 8 divisors (see below), whose sum is σ = 3503484201024. Its totient is φ = 2918848054720.

The previous prime is 3211130022203. The next prime is 3211130022223. The reversal of 3211130022221 is 1222200311123.

3211130022221 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3211130022221 - 230 = 3210056280397 is a prime.

It is a super-3 number, since 3×32111300222213 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3211130022193 and 3211130022202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3211130022223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17959820 + ... + 18137733.

It is an arithmetic number, because the mean of its divisors is an integer number (437935525128).

Almost surely, 23211130022221 is an apocalyptic number.

It is an amenable number.

3211130022221 is a deficient number, since it is larger than the sum of its proper divisors (292354178803).

3211130022221 is a wasteful number, since it uses less digits than its factorization.

3211130022221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36105651.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 3211130022221 its reverse (1222200311123), we get a palindrome (4433330333344).

The spelling of 3211130022221 in words is "three trillion, two hundred eleven billion, one hundred thirty million, twenty-two thousand, two hundred twenty-one".

Divisors: 1 11 8087 88957 36097553 397073083 291920911111 3211130022221