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321145002133 is a prime number
BaseRepresentation
bin1001010110001011011…
…10111101100010010101
31010200221010222102122021
410223011232331202111
520230201110032013
6403310523533141
732126162323024
oct4530556754225
91120833872567
10321145002133
11114218a8837a
12522a698a1b1
132438c7b27a7
141178751c8bb
158548beea8d
hex4ac5bbd895

321145002133 has 2 divisors, whose sum is σ = 321145002134. Its totient is φ = 321145002132.

The previous prime is 321145002077. The next prime is 321145002151. The reversal of 321145002133 is 331200541123.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 321060490884 + 84511249 = 566622^2 + 9193^2 .

It is a cyclic number.

It is not a de Polignac number, because 321145002133 - 213 = 321144993941 is a prime.

It is a super-2 number, since 2×3211450021332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 321145002098 and 321145002107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321145002193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160572501066 + 160572501067.

It is an arithmetic number, because the mean of its divisors is an integer number (160572501067).

Almost surely, 2321145002133 is an apocalyptic number.

It is an amenable number.

321145002133 is a deficient number, since it is larger than the sum of its proper divisors (1).

321145002133 is an equidigital number, since it uses as much as digits as its factorization.

321145002133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 321145002133 its reverse (331200541123), we get a palindrome (652345543256).

The spelling of 321145002133 in words is "three hundred twenty-one billion, one hundred forty-five million, two thousand, one hundred thirty-three".