Base | Representation |
---|---|
bin | 1110100110111101111100… |
… | …10000111000100111110111 |
3 | 11012202010220002020001221212 |
4 | 13103132332100320213313 |
5 | 13202320004120112210 |
6 | 152154045352032035 |
7 | 6523654463535464 |
oct | 723367620704767 |
9 | 135663802201855 |
10 | 32125252504055 |
11 | a266274597aa7 |
12 | 372a10a09261b |
13 | 14c0524127939 |
14 | 7d0c289b266b |
15 | 3aa9b8e3e805 |
hex | 1d37be4389f7 |
32125252504055 has 4 divisors (see below), whose sum is σ = 38550303004872. Its totient is φ = 25700202003240.
The previous prime is 32125252504039. The next prime is 32125252504073. The reversal of 32125252504055 is 55040525252123.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 32125252504055 - 24 = 32125252504039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3212525250401 + ... + 3212525250410.
It is an arithmetic number, because the mean of its divisors is an integer number (9637575751218).
Almost surely, 232125252504055 is an apocalyptic number.
32125252504055 is a deficient number, since it is larger than the sum of its proper divisors (6425050500817).
32125252504055 is an equidigital number, since it uses as much as digits as its factorization.
32125252504055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6425050500816.
The product of its (nonzero) digits is 600000, while the sum is 41.
Adding to 32125252504055 its reverse (55040525252123), we get a palindrome (87165777756178).
The spelling of 32125252504055 in words is "thirty-two trillion, one hundred twenty-five billion, two hundred fifty-two million, five hundred four thousand, fifty-five".
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