Base | Representation |
---|---|
bin | 101110101111111010010… |
… | …101001000000100110101 |
3 | 102101010010110112220111010 |
4 | 232233322111020010311 |
5 | 410113240321142323 |
6 | 10455453134102433 |
7 | 451045513644456 |
oct | 56577225100465 |
9 | 12333113486433 |
10 | 3212540412213 |
11 | 1029481348210 |
12 | 43a74134aa19 |
13 | 1a3c30c48022 |
14 | b16b86ab12d |
15 | 58873ad5c93 |
hex | 2ebfa548135 |
3212540412213 has 16 divisors (see below), whose sum is σ = 4918722163200. Its totient is φ = 1844520810480.
The previous prime is 3212540412167. The next prime is 3212540412217. The reversal of 3212540412213 is 3122140452123.
It is a happy number.
It is not a de Polignac number, because 3212540412213 - 236 = 3143820935477 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3212540412217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2561833833 + ... + 2561835086.
It is an arithmetic number, because the mean of its divisors is an integer number (307420135200).
Almost surely, 23212540412213 is an apocalyptic number.
3212540412213 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
3212540412213 is a deficient number, since it is larger than the sum of its proper divisors (1706181750987).
3212540412213 is a wasteful number, since it uses less digits than its factorization.
3212540412213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5123668952.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 3212540412213 its reverse (3122140452123), we get a palindrome (6334680864336).
The spelling of 3212540412213 in words is "three trillion, two hundred twelve billion, five hundred forty million, four hundred twelve thousand, two hundred thirteen".
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