Base | Representation |
---|---|
bin | 1110100111001000101100… |
… | …00110110000110101011100 |
3 | 11012202200210010001211222110 |
4 | 13103210112012300311130 |
5 | 13202413312412304040 |
6 | 152200442023314020 |
7 | 6524250442003122 |
oct | 723442606606534 |
9 | 135680703054873 |
10 | 32131021213020 |
11 | a268764903474 |
12 | 372b259bab910 |
13 | 14c0c333018b2 |
14 | 7d1214bb5912 |
15 | 3aac055db980 |
hex | 1d39161b0d5c |
32131021213020 has 48 divisors (see below), whose sum is σ = 92161173047328. Its totient is φ = 8359290071040.
The previous prime is 32131021212949. The next prime is 32131021213099. The reversal of 32131021213020 is 2031212013123.
32131021213020 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6530692909 + ... + 6530697828.
It is an arithmetic number, because the mean of its divisors is an integer number (1920024438486).
Almost surely, 232131021213020 is an apocalyptic number.
32131021213020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
32131021213020 is an abundant number, since it is smaller than the sum of its proper divisors (60030151834308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32131021213020 is a wasteful number, since it uses less digits than its factorization.
32131021213020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13061390790 (or 13061390788 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 32131021213020 its reverse (2031212013123), we get a palindrome (34162233226143).
The spelling of 32131021213020 in words is "thirty-two trillion, one hundred thirty-one billion, twenty-one million, two hundred thirteen thousand, twenty".
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