Base | Representation |
---|---|
bin | 1110101001001001011011… |
… | …00111010110110110100111 |
3 | 11020000022011210001121002201 |
4 | 13110210231213112312213 |
5 | 13210031334042010210 |
6 | 152252312102115331 |
7 | 6532245236304163 |
oct | 724445547266647 |
9 | 136008153047081 |
10 | 32200135110055 |
11 | a2950008a5240 |
12 | 374072811bb47 |
13 | 14c75c8caa163 |
14 | 7d46cdc4bca3 |
15 | 3ac8ed01853a |
hex | 1d492d9d6da7 |
32200135110055 has 16 divisors (see below), whose sum is σ = 42153041584800. Its totient is φ = 23418203724160.
The previous prime is 32200135109999. The next prime is 32200135110061. The reversal of 32200135110055 is 55001153100223.
It is not a de Polignac number, because 32200135110055 - 213 = 32200135101863 is a prime.
It is a super-2 number, since 2×322001351100552 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20352501 + ... + 21877489.
It is an arithmetic number, because the mean of its divisors is an integer number (2634565099050).
Almost surely, 232200135110055 is an apocalyptic number.
32200135110055 is a deficient number, since it is larger than the sum of its proper divisors (9952906474745).
32200135110055 is a wasteful number, since it uses less digits than its factorization.
32200135110055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1908914.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 32200135110055 its reverse (55001153100223), we get a palindrome (87201288210278).
The spelling of 32200135110055 in words is "thirty-two trillion, two hundred billion, one hundred thirty-five million, one hundred ten thousand, fifty-five".
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