Base | Representation |
---|---|
bin | 101111000000101001000… |
… | …010111101111010010011 |
3 | 102102211111101022021101010 |
4 | 233000221002331322103 |
5 | 410412033014102243 |
6 | 10512023441142003 |
7 | 452252621233314 |
oct | 57005102757223 |
9 | 12384441267333 |
10 | 3230504050323 |
11 | 103605a354420 |
12 | 44211532a903 |
13 | 1a58347869a4 |
14 | b250035060b |
15 | 59075baa433 |
hex | 2f0290bde93 |
3230504050323 has 48 divisors (see below), whose sum is σ = 5126489121024. Its totient is φ = 1792908541440.
The previous prime is 3230504050309. The next prime is 3230504050331.
3230504050323 is nontrivially palindromic in base 10.
3230504050323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3230504050323 - 212 = 3230504046227 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3230504050393) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4224615 + ... + 4930352.
It is an arithmetic number, because the mean of its divisors is an integer number (106801856688).
Almost surely, 23230504050323 is an apocalyptic number.
3230504050323 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3230504050323 is a deficient number, since it is larger than the sum of its proper divisors (1895985070701).
3230504050323 is a wasteful number, since it uses less digits than its factorization.
3230504050323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9155052 (or 9155035 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 30.
The spelling of 3230504050323 in words is "three trillion, two hundred thirty billion, five hundred four million, fifty thousand, three hundred twenty-three".
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