Base | Representation |
---|---|
bin | 101111001001110111101… |
… | …100010000010100111111 |
3 | 102110210001222112222022002 |
4 | 233021313230100110333 |
5 | 411042331314243403 |
6 | 10520343025412515 |
7 | 453053315463302 |
oct | 57116754202477 |
9 | 12423058488262 |
10 | 3240413431103 |
11 | 103a2849a4912 |
12 | 44401ba9a13b |
13 | 1a6753766404 |
14 | b2ba0444b39 |
15 | 59455b18188 |
hex | 2f277b1053f |
3240413431103 has 4 divisors (see below), whose sum is σ = 3245452954968. Its totient is φ = 3235373907240.
The previous prime is 3240413431091. The next prime is 3240413431117. The reversal of 3240413431103 is 3011343140423.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3240413431103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3240413431153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2519760968 + ... + 2519762253.
It is an arithmetic number, because the mean of its divisors is an integer number (811363238742).
Almost surely, 23240413431103 is an apocalyptic number.
3240413431103 is a deficient number, since it is larger than the sum of its proper divisors (5039523865).
3240413431103 is an equidigital number, since it uses as much as digits as its factorization.
3240413431103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5039523864.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 3240413431103 its reverse (3011343140423), we get a palindrome (6251756571526).
The spelling of 3240413431103 in words is "three trillion, two hundred forty billion, four hundred thirteen million, four hundred thirty-one thousand, one hundred three".
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