Base | Representation |
---|---|
bin | 101111010101001000110… |
… | …010011001101100001111 |
3 | 102111221022010001020100210 |
4 | 233111020302121230033 |
5 | 411242120410240210 |
6 | 10530103315253503 |
7 | 453662156604450 |
oct | 57251062315417 |
9 | 12457263036323 |
10 | 3252511415055 |
11 | 10444229a0261 |
12 | 4464375aa293 |
13 | 1a7930cb6bb6 |
14 | b35cb08b127 |
15 | 59912c90e20 |
hex | 2f548c99b0f |
3252511415055 has 32 divisors (see below), whose sum is σ = 6206034207744. Its totient is φ = 1422216170496.
The previous prime is 3252511415053. The next prime is 3252511415117. The reversal of 3252511415055 is 5505141152523.
It is not a de Polignac number, because 3252511415055 - 21 = 3252511415053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3252511415053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 673395394 + ... + 673400223.
It is an arithmetic number, because the mean of its divisors is an integer number (193938568992).
Almost surely, 23252511415055 is an apocalyptic number.
3252511415055 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3252511415055 is a deficient number, since it is larger than the sum of its proper divisors (2953522792689).
3252511415055 is a wasteful number, since it uses less digits than its factorization.
3252511415055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1346795655.
The product of its (nonzero) digits is 150000, while the sum is 39.
Adding to 3252511415055 its reverse (5505141152523), we get a palindrome (8757652567578).
The spelling of 3252511415055 in words is "three trillion, two hundred fifty-two billion, five hundred eleven million, four hundred fifteen thousand, fifty-five".
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