Base | Representation |
---|---|
bin | 1111000000110101011100… |
… | …01000001000011000100101 |
3 | 11022220010000012201010212022 |
4 | 13200122232020020120211 |
5 | 13311400223220113013 |
6 | 154114235100432525 |
7 | 6645120454615046 |
oct | 740325610103045 |
9 | 138803005633768 |
10 | 33014040004133 |
11 | a5791a29a9731 |
12 | 3852413248745 |
13 | 15562979466b6 |
14 | 821c60bb08cd |
15 | 3c3b86e04008 |
hex | 1e06ae208625 |
33014040004133 has 2 divisors, whose sum is σ = 33014040004134. Its totient is φ = 33014040004132.
The previous prime is 33014040004097. The next prime is 33014040004151. The reversal of 33014040004133 is 33140004041033.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31608660576964 + 1405379427169 = 5622158^2 + 1185487^2 .
It is a cyclic number.
It is not a de Polignac number, because 33014040004133 - 212 = 33014040000037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33014040004163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16507020002066 + 16507020002067.
It is an arithmetic number, because the mean of its divisors is an integer number (16507020002067).
Almost surely, 233014040004133 is an apocalyptic number.
It is an amenable number.
33014040004133 is a deficient number, since it is larger than the sum of its proper divisors (1).
33014040004133 is an equidigital number, since it uses as much as digits as its factorization.
33014040004133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 33014040004133 its reverse (33140004041033), we get a palindrome (66154044045166).
The spelling of 33014040004133 in words is "thirty-three trillion, fourteen billion, forty million, four thousand, one hundred thirty-three".
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