Base | Representation |
---|---|
bin | 1111000000110101011100… |
… | …01000001000011000110111 |
3 | 11022220010000012201010212222 |
4 | 13200122232020020120313 |
5 | 13311400223220113101 |
6 | 154114235100432555 |
7 | 6645120454615103 |
oct | 740325610103067 |
9 | 138803005633788 |
10 | 33014040004151 |
11 | a5791a29a9748 |
12 | 385241324875b |
13 | 15562979466cb |
14 | 821c60bb0903 |
15 | 3c3b86e0401b |
hex | 1e06ae208637 |
33014040004151 has 2 divisors, whose sum is σ = 33014040004152. Its totient is φ = 33014040004150.
The previous prime is 33014040004133. The next prime is 33014040004163. The reversal of 33014040004151 is 15140004041033.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 33014040004151 - 214 = 33014039987767 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 33014040004151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33014049004151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16507020002075 + 16507020002076.
It is an arithmetic number, because the mean of its divisors is an integer number (16507020002076).
Almost surely, 233014040004151 is an apocalyptic number.
33014040004151 is a deficient number, since it is larger than the sum of its proper divisors (1).
33014040004151 is an equidigital number, since it uses as much as digits as its factorization.
33014040004151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 33014040004151 its reverse (15140004041033), we get a palindrome (48154044045184).
The spelling of 33014040004151 in words is "thirty-three trillion, fourteen billion, forty million, four thousand, one hundred fifty-one".
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