Base | Representation |
---|---|
bin | 1100010101001100… |
… | …0001111010010101 |
3 | 22112200112111201122 |
4 | 3011103001322111 |
5 | 23234341200432 |
6 | 1304242533325 |
7 | 145012246442 |
oct | 30523017225 |
9 | 8480474648 |
10 | 3310100117 |
11 | 1449513235 |
12 | 784667245 |
13 | 409a0a62c |
14 | 2358889c9 |
15 | 1458ea612 |
hex | c54c1e95 |
3310100117 has 2 divisors, whose sum is σ = 3310100118. Its totient is φ = 3310100116.
The previous prime is 3310100111. The next prime is 3310100173. The reversal of 3310100117 is 7110010133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2072889841 + 1237210276 = 45529^2 + 35174^2 .
It is a cyclic number.
It is not a de Polignac number, because 3310100117 - 28 = 3310099861 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3310100095 and 3310100104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3310100111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655050058 + 1655050059.
It is an arithmetic number, because the mean of its divisors is an integer number (1655050059).
Almost surely, 23310100117 is an apocalyptic number.
It is an amenable number.
3310100117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3310100117 is an equidigital number, since it uses as much as digits as its factorization.
3310100117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 17.
The square root of 3310100117 is about 57533.4695373050. The cubic root of 3310100117 is about 1490.3229060083.
The spelling of 3310100117 in words is "three billion, three hundred ten million, one hundred thousand, one hundred seventeen".
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