331111111111133 has 2 divisors, whose sum is σ = 331111111111134. Its totient is φ = 331111111111132.

The previous prime is 331111111111127. The next prime is 331111111111139.

331111111111133 is nontrivially palindromic in base 10.

It is a balanced prime because it is at equal distance from previous prime (331111111111127) and next prime (331111111111139).

It can be written as a sum of positive squares in only one way, i.e., 168580153080964 + 162530958030169 = 12983842^2 + 12748763^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 331111111111133 - 2¹⁴ = 331111111094749 is a prime.

It is a zygodrome in base 10.

It is a junction number, because it is equal to n+sod(n) for n = 331111111111099 and 331111111111108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331111111111139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165555555555566 + 165555555555567.

It is an arithmetic number, because the mean of its divisors is an integer number (165555555555567).

Almost surely, 2^{331111111111133} is an apocalyptic number.

It is an amenable number.

331111111111133 is a deficient number, since it is larger than the sum of its proper divisors (1).

331111111111133 is an equidigital number, since it uses as much as digits as its factorization.

331111111111133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 81, while the sum is 23.

The spelling of 331111111111133 in words is "three hundred thirty-one trillion, one hundred eleven billion, one hundred eleven million, one hundred eleven thousand, one hundred thirty-three".