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3312302194919 is a prime number
BaseRepresentation
bin110000001100110100100…
…110001000000011100111
3102201122122000221120001002
4300030310212020003213
5413232043330214134
611013352311223515
7461206636054064
oct60146446100347
912648560846032
103312302194919
111067815268113
12455b43377b9b
131b046c2ac193
14b645dc3bc6b
155b261e6787e
hex303349880e7

3312302194919 has 2 divisors, whose sum is σ = 3312302194920. Its totient is φ = 3312302194918.

The previous prime is 3312302194913. The next prime is 3312302194921. The reversal of 3312302194919 is 9194912032133.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3312302194919 - 224 = 3312285417703 is a prime.

It is a super-2 number, since 2×33123021949192 (a number of 26 digits) contains 22 as substring.

Together with 3312302194921, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3312302194913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656151097459 + 1656151097460.

It is an arithmetic number, because the mean of its divisors is an integer number (1656151097460).

Almost surely, 23312302194919 is an apocalyptic number.

3312302194919 is a deficient number, since it is larger than the sum of its proper divisors (1).

3312302194919 is an equidigital number, since it uses as much as digits as its factorization.

3312302194919 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 314928, while the sum is 47.

The spelling of 3312302194919 in words is "three trillion, three hundred twelve billion, three hundred two million, one hundred ninety-four thousand, nine hundred nineteen".