Base | Representation |
---|---|
bin | 1111000100010011011001… |
… | …01001001000001010111000 |
3 | 11100022111120201002120200102 |
4 | 13202021230221020022320 |
5 | 13320323243303121130 |
6 | 154245103202254532 |
7 | 6656536410621416 |
oct | 742115451101270 |
9 | 140274521076612 |
10 | 33133200442040 |
11 | a614790961386 |
12 | 3871529957448 |
13 | 15645a7c0875a |
14 | 8279268102b6 |
15 | 3c6d0d31a645 |
hex | 1e226ca482b8 |
33133200442040 has 16 divisors (see below), whose sum is σ = 74549700994680. Its totient is φ = 13253280176800.
The previous prime is 33133200441953. The next prime is 33133200442081. The reversal of 33133200442040 is 4024400233133.
It is a junction number, because it is equal to n+sod(n) for n = 33133200441994 and 33133200442012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 414165005486 + ... + 414165005565.
Almost surely, 233133200442040 is an apocalyptic number.
It is an amenable number.
33133200442040 is an abundant number, since it is smaller than the sum of its proper divisors (41416500552640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33133200442040 is a wasteful number, since it uses less digits than its factorization.
33133200442040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 828330011062 (or 828330011058 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 33133200442040 its reverse (4024400233133), we get a palindrome (37157600675173).
The spelling of 33133200442040 in words is "thirty-three trillion, one hundred thirty-three billion, two hundred million, four hundred forty-two thousand, forty".
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