Base | Representation |
---|---|
bin | 100101101111101000001100… |
… | …1101101011110001011101000 |
3 | 1121112112000122122002210221210 |
4 | 1023133100121231132023220 |
5 | 322004002333223100204 |
6 | 3134035201130433120 |
7 | 126634211162613300 |
oct | 11337203155361350 |
9 | 1545460578083853 |
10 | 332001403331304 |
11 | 96871005a159a3 |
12 | 312a011a2927a0 |
13 | 113337a0a52285 |
14 | 5bdad4cbb0600 |
15 | 285b1b9917389 |
hex | 12df419b5e2e8 |
332001403331304 has 48 divisors (see below), whose sum is σ = 965514285201600. Its totient is φ = 94857543808608.
The previous prime is 332001403331261. The next prime is 332001403331371. The reversal of 332001403331304 is 403133304100233.
It is a super-2 number, since 2×3320014033313042 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 141157058064 + ... + 141157060415.
It is an arithmetic number, because the mean of its divisors is an integer number (20114880941700).
Almost surely, 2332001403331304 is an apocalyptic number.
It is an amenable number.
332001403331304 is an abundant number, since it is smaller than the sum of its proper divisors (633512881870296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
332001403331304 is a wasteful number, since it uses less digits than its factorization.
332001403331304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282314118502 (or 282314118491 counting only the distinct ones).
The product of its (nonzero) digits is 23328, while the sum is 30.
Adding to 332001403331304 its reverse (403133304100233), we get a palindrome (735134707431537).
The spelling of 332001403331304 in words is "three hundred thirty-two trillion, one billion, four hundred three million, three hundred thirty-one thousand, three hundred four".
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