Base | Representation |
---|---|
bin | 1100010111110100… |
… | …0000001010101111 |
3 | 22120110020111212200 |
4 | 3011331000022233 |
5 | 23300200244043 |
6 | 1305314432543 |
7 | 145204624050 |
oct | 30575001257 |
9 | 8513214780 |
10 | 3321103023 |
11 | 1454748947 |
12 | 788292753 |
13 | 40c090824 |
14 | 237110727 |
15 | 1468707d3 |
hex | c5f402af |
3321103023 has 24 divisors (see below), whose sum is σ = 5491762848. Its totient is φ = 1894551552.
The previous prime is 3321103007. The next prime is 3321103039. The reversal of 3321103023 is 3203011233.
3321103023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (3321103007) and next prime (3321103039).
It is not a de Polignac number, because 3321103023 - 24 = 3321103007 is a prime.
It is a super-2 number, since 2×33211030232 = 22059450578759477058, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3321102987 and 3321103005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3321103063) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7090 + ... + 81807.
It is an arithmetic number, because the mean of its divisors is an integer number (228823452).
Almost surely, 23321103023 is an apocalyptic number.
3321103023 is a deficient number, since it is larger than the sum of its proper divisors (2170659825).
3321103023 is a wasteful number, since it uses less digits than its factorization.
3321103023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89503 (or 89500 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
The square root of 3321103023 is about 57629.0119904897. The cubic root of 3321103023 is about 1491.9723774915.
Adding to 3321103023 its reverse (3203011233), we get a palindrome (6524114256).
It can be divided in two parts, 332 and 1103023, that added together give a triangular number (1103355 = T1485).
The spelling of 3321103023 in words is "three billion, three hundred twenty-one million, one hundred three thousand, twenty-three".
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