Base | Representation |
---|---|
bin | 1100011000101111… |
… | …1000100101100101 |
3 | 22120201120201012020 |
4 | 3012023320211211 |
5 | 23302200113013 |
6 | 1305534213353 |
7 | 145253032413 |
oct | 30613704545 |
9 | 8521521166 |
10 | 3325004133 |
11 | 1456972900 |
12 | 789654259 |
13 | 40cb28389 |
14 | 2378482b3 |
15 | 146d91623 |
hex | c62f8965 |
3325004133 has 48 divisors (see below), whose sum is σ = 4981435200. Its totient is φ = 1970848000.
The previous prime is 3325004129. The next prime is 3325004171. The reversal of 3325004133 is 3314005233.
It is a happy number.
3325004133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3325004133 - 22 = 3325004129 is a prime.
It is a super-2 number, since 2×33250041332 = 22111304968934163378, which contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3325004113) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3262498 + ... + 3263516.
It is an arithmetic number, because the mean of its divisors is an integer number (103779900).
Almost surely, 23325004133 is an apocalyptic number.
3325004133 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
3325004133 is a deficient number, since it is larger than the sum of its proper divisors (1656431067).
3325004133 is a wasteful number, since it uses less digits than its factorization.
3325004133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1234 (or 1223 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 24.
The square root of 3325004133 is about 57662.8488109979. The cubic root of 3325004133 is about 1492.5563271476.
Adding to 3325004133 its reverse (3314005233), we get a palindrome (6639009366).
It can be divided in two parts, 332500 and 4133, that added together give a palindrome (336633).
The spelling of 3325004133 in words is "three billion, three hundred twenty-five million, four thousand, one hundred thirty-three".
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