3330000041 has 2 divisors, whose sum is σ = 3330000042. Its totient is φ = 3330000040.

The previous prime is 3329999989. The next prime is 3330000043. The reversal of 3330000041 is 1400000333.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2693194816 + 636805225 = 51896^2 + 25235^2 .

It is a cyclic number.

It is not a de Polignac number, because 3330000041 - 2⁶ = 3329999977 is a prime.

It is a super-2 number, since 2×3330000041² = 22177800546120003362, which contains 22 as substring.

Together with 3330000043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3329999980 and 3330000025.

It is not a weakly prime, because it can be changed into another prime (3330000043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665000020 + 1665000021.

It is an arithmetic number, because the mean of its divisors is an integer number (1665000021).

Almost surely, 2^3330000041 is an apocalyptic number.

It is an amenable number.

3330000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3330000041 is an equidigital number, since it uses as much as digits as its factorization.

3330000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 14.

The square root of 3330000041 is about 57706.1525402621. The cubic root of 3330000041 is about 1493.3034883834.

Adding to 3330000041 its reverse (1400000333), we get a palindrome (4730000374).

The spelling of 3330000041 in words is "three billion, three hundred thirty million, forty-one", and thus it is an aban number.