Base | Representation |
---|---|
bin | 1111001001001100001011… |
… | …00000011100010001010100 |
3 | 11100220120000101212000120110 |
4 | 13210212011200130101110 |
5 | 13331101144024220040 |
6 | 154454153545403020 |
7 | 10004632554546351 |
oct | 744460540342124 |
9 | 140816011760513 |
10 | 33301121320020 |
11 | a679a20910394 |
12 | 3899b92199470 |
13 | 15773891a4908 |
14 | 831ad62b3628 |
15 | 3cb38a374980 |
hex | 1e498581c454 |
33301121320020 has 96 divisors (see below), whose sum is σ = 95519212903296. Its totient is φ = 8663538534400.
The previous prime is 33301121320013. The next prime is 33301121320063. The reversal of 33301121320020 is 2002312110333.
It is a super-2 number, since 2×333011213200202 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 173745040 + ... + 173936600.
It is an arithmetic number, because the mean of its divisors is an integer number (994991801076).
Almost surely, 233301121320020 is an apocalyptic number.
33301121320020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
33301121320020 is an abundant number, since it is smaller than the sum of its proper divisors (62218091583276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33301121320020 is a wasteful number, since it uses less digits than its factorization.
33301121320020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262281 (or 262279 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 33301121320020 its reverse (2002312110333), we get a palindrome (35303433430353).
The spelling of 33301121320020 in words is "thirty-three trillion, three hundred one billion, one hundred twenty-one million, three hundred twenty thousand, twenty".
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