3340121333 has 4 divisors (see below), whose sum is σ = 3340880928. Its totient is φ = 3339361740.

The previous prime is 3340121311. The next prime is 3340121339. The reversal of 3340121333 is 3331210433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3340121333 - 2⁶ = 3340121269 is a prime.

It is a super-2 number, since 2×3340121333² = 22312821038323393778, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3340121299 and 3340121308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3340121339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373163 + ... + 382008.

It is an arithmetic number, because the mean of its divisors is an integer number (835220232).

Almost surely, 2^3340121333 is an apocalyptic number.

It is an amenable number.

3340121333 is a deficient number, since it is larger than the sum of its proper divisors (759595).

3340121333 is an equidigital number, since it uses as much as digits as its factorization.

3340121333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 759594.

The product of its (nonzero) digits is 1944, while the sum is 23.

The square root of 3340121333 is about 57793.7828230684. The cubic root of 3340121333 is about 1494.8148871295.

Adding to 3340121333 its reverse (3331210433), we get a palindrome (6671331766).

The spelling of 3340121333 in words is "three billion, three hundred forty million, one hundred twenty-one thousand, three hundred thirty-three".