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336153131020020 = 2235169711239293749
BaseRepresentation
bin100110001101110101011111…
…1111101101110111011110100
31122002012220222200012201010110
41030123222333331232323310
5323030013103020120040
63150534341055423020
7130543155645654126
oct11433527775567364
91562186880181113
10336153131020020
1198121818a6a826
123185088b524a70
131157514801c672
145d01c81113216
1528ce1aaec4980
hex131babff6eef4

336153131020020 has 96 divisors (see below), whose sum is σ = 941870412000000. Its totient is φ = 89579735691264.

The previous prime is 336153131020013. The next prime is 336153131020111. The reversal of 336153131020020 is 20020131351633.

It is a super-3 number, since 3×3361531310200203 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 336153131020020.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1144208106 + ... + 1144501854.

It is an arithmetic number, because the mean of its divisors is an integer number (9811150125000).

Almost surely, 2336153131020020 is an apocalyptic number.

336153131020020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

336153131020020 is an abundant number, since it is smaller than the sum of its proper divisors (605717280979980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

336153131020020 is a wasteful number, since it uses less digits than its factorization.

336153131020020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306697 (or 306695 counting only the distinct ones).

The product of its (nonzero) digits is 9720, while the sum is 30.

Adding to 336153131020020 its reverse (20020131351633), we get a palindrome (356173262371653).

The spelling of 336153131020020 in words is "three hundred thirty-six trillion, one hundred fifty-three billion, one hundred thirty-one million, twenty thousand, twenty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 1697 3394 5091 6788 8485 10182 11239 16970 20364 22478 25455 33717 33940 44956 50910 56195 67434 101820 112390 134868 168585 224780 293749 337170 587498 674340 881247 1174996 1468745 1762494 2937490 3524988 4406235 5874980 8812470 17624940 19072583 38145166 57217749 76290332 95362915 114435498 190725830 228870996 286088745 381451660 498492053 572177490 996984106 1144354980 1495476159 1993968212 2492460265 2990952318 3301445011 4984920530 5981904636 6602890022 7477380795 9904335033 9969841060 13205780044 14954761590 16507225055 19808670066 29909523180 33014450110 39617340132 49521675165 66028900220 99043350330 198086700660 5602552183667 11205104367334 16807656551001 22410208734668 28012760918335 33615313102002 56025521836670 67230626204004 84038282755005 112051043673340 168076565510010 336153131020020