Base | Representation |
---|---|
bin | 110001011111101101100… |
… | …001100111100111001111 |
3 | 110001011100201211001010222 |
4 | 301133231201213213033 |
5 | 421211332330104320 |
6 | 11122312040021555 |
7 | 500510326126136 |
oct | 61375541474717 |
9 | 13034321731128 |
10 | 3401304144335 |
11 | 10a1537577009 |
12 | 46b241a618bb |
13 | 1b89843c7686 |
14 | ba8a437891d |
15 | 5d72089a825 |
hex | 317ed8679cf |
3401304144335 has 8 divisors (see below), whose sum is σ = 4081617981936. Its totient is φ = 2721007976320.
The previous prime is 3401304144319. The next prime is 3401304144367. The reversal of 3401304144335 is 5334414031043.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3401304144335 - 24 = 3401304144319 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3401304144295 and 3401304144304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3990149 + ... + 4766958.
It is an arithmetic number, because the mean of its divisors is an integer number (510202247742).
Almost surely, 23401304144335 is an apocalyptic number.
3401304144335 is a deficient number, since it is larger than the sum of its proper divisors (680313837601).
3401304144335 is an equidigital number, since it uses as much as digits as its factorization.
3401304144335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8834793.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 3401304144335 its reverse (5334414031043), we get a palindrome (8735718175378).
The spelling of 3401304144335 in words is "three trillion, four hundred one billion, three hundred four million, one hundred forty-four thousand, three hundred thirty-five".
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