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34041501431221 is a prime number
BaseRepresentation
bin1111011110101111001111…
…00110011011010110110101
311110112100001202122121100111
413233113213212123112311
513430213443331244341
6200222241100543021
710112263065631534
oct757274746332665
9143470052577314
1034041501431221
11a934a13109209
123999579b51a71
1315cc13b390a7b
1485989045031b
153e076e499681
hex1ef5e799b5b5

34041501431221 has 2 divisors, whose sum is σ = 34041501431222. Its totient is φ = 34041501431220.

The previous prime is 34041501431219. The next prime is 34041501431239. The reversal of 34041501431221 is 12213410514043.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17162468703121 + 16879032728100 = 4142761^2 + 4108410^2 .

It is a cyclic number.

It is not a de Polignac number, because 34041501431221 - 21 = 34041501431219 is a prime.

Together with 34041501431219, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34041501531221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17020750715610 + 17020750715611.

It is an arithmetic number, because the mean of its divisors is an integer number (17020750715611).

Almost surely, 234041501431221 is an apocalyptic number.

It is an amenable number.

34041501431221 is a deficient number, since it is larger than the sum of its proper divisors (1).

34041501431221 is an equidigital number, since it uses as much as digits as its factorization.

34041501431221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 34041501431221 its reverse (12213410514043), we get a palindrome (46254911945264).

The spelling of 34041501431221 in words is "thirty-four trillion, forty-one billion, five hundred one million, four hundred thirty-one thousand, two hundred twenty-one".