Base | Representation |
---|---|
bin | 11111110000100101… |
… | …001011110001000001 |
3 | 10021000120010211221220 |
4 | 133300211023301001 |
5 | 1024314332103213 |
6 | 23355451505253 |
7 | 2315025101052 |
oct | 376045136101 |
9 | 107016124856 |
10 | 34101050433 |
11 | 1350a176a0a |
12 | 6738458229 |
13 | 32a5c07468 |
14 | 1916d84729 |
15 | d48baee23 |
hex | 7f094bc41 |
34101050433 has 4 divisors (see below), whose sum is σ = 45468067248. Its totient is φ = 22734033620.
The previous prime is 34101050429. The next prime is 34101050443. The reversal of 34101050433 is 33405010143.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34101050433 - 22 = 34101050429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (34101050443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5683508403 + ... + 5683508408.
It is an arithmetic number, because the mean of its divisors is an integer number (11367016812).
Almost surely, 234101050433 is an apocalyptic number.
It is an amenable number.
34101050433 is a deficient number, since it is larger than the sum of its proper divisors (11367016815).
34101050433 is a wasteful number, since it uses less digits than its factorization.
34101050433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11367016814.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 34101050433 its reverse (33405010143), we get a palindrome (67506060576).
The spelling of 34101050433 in words is "thirty-four billion, one hundred one million, fifty thousand, four hundred thirty-three".
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