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341012001133023 = 31110333697004031
BaseRepresentation
bin100110110001001100000101…
…1001100010001000111011111
31122201102102120200112202012220
41031202120023030101013133
5324144120034242224043
63205134430045000423
7131554206200325633
oct11542301314210737
91581372520482186
10341012001133023
1199725417525340
12322b64b1253113
13118383a840854c
14602d0d718cdc3
1529657886d8483
hex136260b3111df

341012001133023 has 8 divisors (see below), whose sum is σ = 496017456193536. Its totient is φ = 206673940080600.

The previous prime is 341012001133009. The next prime is 341012001133033. The reversal of 341012001133023 is 320331100210143.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 341012001133023 - 210 = 341012001131999 is a prime.

It is a super-2 number, since 2×3410120011330232 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 341012001132984 and 341012001133002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341012001133033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5166848501983 + ... + 5166848502048.

It is an arithmetic number, because the mean of its divisors is an integer number (62002182024192).

Almost surely, 2341012001133023 is an apocalyptic number.

341012001133023 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

341012001133023 is a deficient number, since it is larger than the sum of its proper divisors (155005455060513).

341012001133023 is a wasteful number, since it uses less digits than its factorization.

341012001133023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10333697004045.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 341012001133023 its reverse (320331100210143), we get a palindrome (661343101343166).

The spelling of 341012001133023 in words is "three hundred forty-one trillion, twelve billion, one million, one hundred thirty-three thousand, twenty-three".

Divisors: 1 3 11 33 10333697004031 31001091012093 113670667044341 341012001133023