Base | Representation |
---|---|
bin | 110001101000110110100… |
… | …111011100001111110011 |
3 | 110002002200211201112212120 |
4 | 301220312213130033303 |
5 | 421341433301421003 |
6 | 11131014055125323 |
7 | 501305512335213 |
oct | 61506647341763 |
9 | 13062624645776 |
10 | 3411120342003 |
11 | 10a5714561670 |
12 | 471121373843 |
13 | 1b9889cac36a |
14 | bb155d34243 |
15 | 5dae754d853 |
hex | 31a369dc3f3 |
3411120342003 has 64 divisors (see below), whose sum is σ = 5068367216640. Its totient is φ = 2023205184000.
The previous prime is 3411120341999. The next prime is 3411120342011. The reversal of 3411120342003 is 3002430211143.
It is a happy number.
3411120342003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3411120342003 - 22 = 3411120341999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3411120342023) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 477009478 + ... + 477016628.
It is an arithmetic number, because the mean of its divisors is an integer number (79193237760).
Almost surely, 23411120342003 is an apocalyptic number.
3411120342003 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3411120342003 is a deficient number, since it is larger than the sum of its proper divisors (1657246874637).
3411120342003 is a wasteful number, since it uses less digits than its factorization.
3411120342003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8288.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 3411120342003 its reverse (3002430211143), we get a palindrome (6413550553146).
The spelling of 3411120342003 in words is "three trillion, four hundred eleven billion, one hundred twenty million, three hundred forty-two thousand, three".
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