Base | Representation |
---|---|
bin | 1100101101100111… |
… | …0010010011000111 |
3 | 22210211021201020121 |
4 | 3023121302103013 |
5 | 23442102100341 |
6 | 1322342242411 |
7 | 150365031043 |
oct | 31331622307 |
9 | 8724251217 |
10 | 3412534471 |
11 | 14a1317725 |
12 | 7b2a26407 |
13 | 424cc4188 |
14 | 245311023 |
15 | 14e8d14d1 |
hex | cb6724c7 |
3412534471 has 2 divisors, whose sum is σ = 3412534472. Its totient is φ = 3412534470.
The previous prime is 3412534451. The next prime is 3412534483. The reversal of 3412534471 is 1744352143.
It is a strong prime.
It is an emirp because it is prime and its reverse (1744352143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3412534471 - 211 = 3412532423 is a prime.
It is a super-3 number, since 3×34125344713 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3412534421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706267235 + 1706267236.
It is an arithmetic number, because the mean of its divisors is an integer number (1706267236).
Almost surely, 23412534471 is an apocalyptic number.
3412534471 is a deficient number, since it is larger than the sum of its proper divisors (1).
3412534471 is an equidigital number, since it uses as much as digits as its factorization.
3412534471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40320, while the sum is 34.
The square root of 3412534471 is about 58416.9022715173. The cubic root of 3412534471 is about 1505.5401748201.
The spelling of 3412534471 in words is "three billion, four hundred twelve million, five hundred thirty-four thousand, four hundred seventy-one".
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