Base | Representation |
---|---|
bin | 110001110001001110100… |
… | …001101001110000011101 |
3 | 110002221220110000020120102 |
4 | 301301032201221300131 |
5 | 422013342010143003 |
6 | 11135102201030445 |
7 | 502044356225054 |
oct | 61611641516035 |
9 | 13087813006512 |
10 | 3420111412253 |
11 | 10a9508803838 |
12 | 472a10485425 |
13 | 1ba690953c83 |
14 | bb76a0a339b |
15 | 5de71a64588 |
hex | 31c4e869c1d |
3420111412253 has 2 divisors, whose sum is σ = 3420111412254. Its totient is φ = 3420111412252.
The previous prime is 3420111412177. The next prime is 3420111412303. The reversal of 3420111412253 is 3522141110243.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3103157050084 + 316954362169 = 1761578^2 + 562987^2 .
It is a cyclic number.
It is not a de Polignac number, because 3420111412253 - 222 = 3420107217949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3420111712253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710055706126 + 1710055706127.
It is an arithmetic number, because the mean of its divisors is an integer number (1710055706127).
Almost surely, 23420111412253 is an apocalyptic number.
It is an amenable number.
3420111412253 is a deficient number, since it is larger than the sum of its proper divisors (1).
3420111412253 is an equidigital number, since it uses as much as digits as its factorization.
3420111412253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 3420111412253 its reverse (3522141110243), we get a palindrome (6942252522496).
The spelling of 3420111412253 in words is "three trillion, four hundred twenty billion, one hundred eleven million, four hundred twelve thousand, two hundred fifty-three".
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