342434120130 has 96 divisors (see below), whose sum is σ = 929419440768. Its totient is φ = 90710928000.

The previous prime is 342434120089. The next prime is 342434120143. The reversal of 342434120130 is 31021434243.

342434120130 is a `hidden beast` number, since 3 + 4 + 243 + 412 + 0 + 1 + 3 + 0 = 666.

It is a super-4 number, since 4×342434120130⁴ (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 342434120094 and 342434120103.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 99691 + ... + 833550.

It is an arithmetic number, because the mean of its divisors is an integer number (9681452508).

Almost surely, 2^342434120130 is an apocalyptic number.

342434120130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 342434120130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (464709720384).

342434120130 is an abundant number, since it is smaller than the sum of its proper divisors (586985320638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

342434120130 is a wasteful number, since it uses less digits than its factorization.

342434120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 933414 (or 933402 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 342434120130 its reverse (31021434243), we get a palindrome (373455554373).

The spelling of 342434120130 in words is "three hundred forty-two billion, four hundred thirty-four million, one hundred twenty thousand, one hundred thirty".