343431312149 has 2 divisors, whose sum is σ = 343431312150. Its totient is φ = 343431312148.

The previous prime is 343431312041. The next prime is 343431312151. The reversal of 343431312149 is 941213134343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 175284568900 + 168146743249 = 418670^2 + 410057^2 .

It is a cyclic number.

It is not a de Polignac number, because 343431312149 - 2³² = 339136344853 is a prime.

It is a super-3 number, since 3×343431312149³ (a number of 36 digits) contains 333 as substring.

Together with 343431312151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (343437312149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171715656074 + 171715656075.

It is an arithmetic number, because the mean of its divisors is an integer number (171715656075).

Almost surely, 2^343431312149 is an apocalyptic number.

It is an amenable number.

343431312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

343431312149 is an equidigital number, since it uses as much as digits as its factorization.

343431312149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 38.

The spelling of 343431312149 in words is "three hundred forty-three billion, four hundred thirty-one million, three hundred twelve thousand, one hundred forty-nine".