Base | Representation |
---|---|
bin | 11111111111000111… |
… | …110010000000111101 |
3 | 10021122120011211020212 |
4 | 133333013302000331 |
5 | 1030314310013041 |
6 | 23440004322205 |
7 | 2324046456212 |
oct | 377707620075 |
9 | 107576154225 |
10 | 34345001021 |
11 | 13624948671 |
12 | 67a60a3365 |
13 | 331460c516 |
14 | 193b527b09 |
15 | d602eb8eb |
hex | 7ff1f203d |
34345001021 has 2 divisors, whose sum is σ = 34345001022. Its totient is φ = 34345001020.
The previous prime is 34345000993. The next prime is 34345001023. The reversal of 34345001021 is 12010054343.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18066048100 + 16278952921 = 134410^2 + 127589^2 .
It is a cyclic number.
It is not a de Polignac number, because 34345001021 - 218 = 34344738877 is a prime.
Together with 34345001023, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34345001023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17172500510 + 17172500511.
It is an arithmetic number, because the mean of its divisors is an integer number (17172500511).
Almost surely, 234345001021 is an apocalyptic number.
It is an amenable number.
34345001021 is a deficient number, since it is larger than the sum of its proper divisors (1).
34345001021 is an equidigital number, since it uses as much as digits as its factorization.
34345001021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 34345001021 its reverse (12010054343), we get a palindrome (46355055364).
The spelling of 34345001021 in words is "thirty-four billion, three hundred forty-five million, one thousand, twenty-one".
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