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34345001021 is a prime number
BaseRepresentation
bin11111111111000111…
…110010000000111101
310021122120011211020212
4133333013302000331
51030314310013041
623440004322205
72324046456212
oct377707620075
9107576154225
1034345001021
1113624948671
1267a60a3365
13331460c516
14193b527b09
15d602eb8eb
hex7ff1f203d

34345001021 has 2 divisors, whose sum is σ = 34345001022. Its totient is φ = 34345001020.

The previous prime is 34345000993. The next prime is 34345001023. The reversal of 34345001021 is 12010054343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18066048100 + 16278952921 = 134410^2 + 127589^2 .

It is a cyclic number.

It is not a de Polignac number, because 34345001021 - 218 = 34344738877 is a prime.

Together with 34345001023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34345001023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17172500510 + 17172500511.

It is an arithmetic number, because the mean of its divisors is an integer number (17172500511).

Almost surely, 234345001021 is an apocalyptic number.

It is an amenable number.

34345001021 is a deficient number, since it is larger than the sum of its proper divisors (1).

34345001021 is an equidigital number, since it uses as much as digits as its factorization.

34345001021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 34345001021 its reverse (12010054343), we get a palindrome (46355055364).

The spelling of 34345001021 in words is "thirty-four billion, three hundred forty-five million, one thousand, twenty-one".