34352311325343 has 24 divisors (see below), whose sum is σ = 50366682126768. Its totient is φ = 20810838048000.

The previous prime is 34352311325281. The next prime is 34352311325351.

34352311325343 is nontrivially palindromic in base 10.

It is a de Polignac number, because none of the positive numbers 2^k-34352311325343 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34352311325295 and 34352311325304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34352311325243) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19008538 + ... + 20737143.

It is an arithmetic number, because the mean of its divisors is an integer number (2098611755282).

Almost surely, 2^{34352311325343} is an apocalyptic number.

34352311325343 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

34352311325343 is a deficient number, since it is larger than the sum of its proper divisors (16014370801425).

34352311325343 is a wasteful number, since it uses less digits than its factorization.

34352311325343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39748087 (or 39748076 counting only the distinct ones).

The product of its digits is 1166400, while the sum is 42.

The spelling of 34352311325343 in words is "thirty-four trillion, three hundred fifty-two billion, three hundred eleven million, three hundred twenty-five thousand, three hundred forty-three".