Base | Representation |
---|---|
bin | 100111001111000101100010… |
… | …1110101000011010100000111 |
3 | 1200020222020221022202012201100 |
4 | 1032132023011311003110013 |
5 | 330213431024001342133 |
6 | 3222002242043031143 |
7 | 132460115053044264 |
oct | 11636130565032407 |
9 | 1606866838665640 |
10 | 345121121121543 |
11 | 9aa6a0556473a8 |
12 | 3285a95120b4b3 |
13 | 11a75a222b5610 |
14 | 6131d4687a26b |
15 | 29d75d43abe13 |
hex | 139e2c5d43507 |
345121121121543 has 12 divisors (see below), whose sum is σ = 536855077300360. Its totient is φ = 212382228382416.
The previous prime is 345121121121499. The next prime is 345121121121577.
345121121121543 is a `hidden beast` number, since 3 + 4 + 51 + 21 + 1 + 21 + 1 + 21 + 543 = 666.
345121121121543 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 345121121121543 - 210 = 345121121120519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 345121121121498 and 345121121121507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (345121121123543) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1474876585873 + ... + 1474876586106.
Almost surely, 2345121121121543 is an apocalyptic number.
345121121121543 is a deficient number, since it is larger than the sum of its proper divisors (191733956178817).
345121121121543 is a wasteful number, since it uses less digits than its factorization.
345121121121543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2949753171998 (or 2949753171995 counting only the distinct ones).
The product of its digits is 28800, while the sum is 36.
The spelling of 345121121121543 in words is "three hundred forty-five trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred twenty-one thousand, five hundred forty-three".
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