Search a number
-
+
350013301 = 1131819391
BaseRepresentation
bin10100110111001…
…100011101110101
3220101121111222121
4110313030131311
51204100411201
654421555541
711450030641
oct2467143565
9811544877
10350013301
1116a6341a0
1299275bb1
135768c281
14346b1c21
1520adc9a1
hex14dcc775

350013301 has 4 divisors (see below), whose sum is σ = 381832704. Its totient is φ = 318193900.

The previous prime is 350013283. The next prime is 350013317. The reversal of 350013301 is 103310053.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 350013301 - 211 = 350011253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (350016301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15909685 + ... + 15909706.

It is an arithmetic number, because the mean of its divisors is an integer number (95458176).

Almost surely, 2350013301 is an apocalyptic number.

It is an amenable number.

350013301 is a deficient number, since it is larger than the sum of its proper divisors (31819403).

350013301 is a wasteful number, since it uses less digits than its factorization.

350013301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31819402.

The product of its (nonzero) digits is 135, while the sum is 16.

The square root of 350013301 is about 18708.6424146703. The cubic root of 350013301 is about 704.7388003430.

Adding to 350013301 its reverse (103310053), we get a palindrome (453323354).

The spelling of 350013301 in words is "three hundred fifty million, thirteen thousand, three hundred one".

Divisors: 1 11 31819391 350013301