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351000121 is a prime number
BaseRepresentation
bin10100111010111…
…101011000111001
3220110110122122111
4110322331120321
51204324000441
654455052321
711461310653
oct2472753071
9813418574
10351000121
1117014864a
12996710a1
13579464a4
143488b6d3
1520c35081
hex14ebd639

351000121 has 2 divisors, whose sum is σ = 351000122. Its totient is φ = 351000120.

The previous prime is 351000109. The next prime is 351000131. The reversal of 351000121 is 121000153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 326199721 + 24800400 = 18061^2 + 4980^2 .

It is an emirp because it is prime and its reverse (121000153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 351000121 - 219 = 350475833 is a prime.

It is not a weakly prime, because it can be changed into another prime (351000131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175500060 + 175500061.

It is an arithmetic number, because the mean of its divisors is an integer number (175500061).

Almost surely, 2351000121 is an apocalyptic number.

It is an amenable number.

351000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

351000121 is an equidigital number, since it uses as much as digits as its factorization.

351000121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 351000121 is about 18734.9972244460. The cubic root of 351000121 is about 705.4004873736.

Adding to 351000121 its reverse (121000153), we get a palindrome (472000274).

The spelling of 351000121 in words is "three hundred fifty-one million, one hundred twenty-one", and thus it is an aban number.