Base | Representation |
---|---|
bin | 100000101101100100… |
… | …101111010011001101 |
3 | 10100122212122112212010 |
4 | 200231210233103031 |
5 | 1033413313002023 |
6 | 24045204331433 |
7 | 2352261666213 |
oct | 405544572315 |
9 | 110585575763 |
10 | 35124344013 |
11 | 1399485a590 |
12 | 69830a3b79 |
13 | 3409c0bc15 |
14 | 19b2c36cb3 |
15 | da8943093 |
hex | 82d92f4cd |
35124344013 has 8 divisors (see below), whose sum is σ = 51089954976. Its totient is φ = 21287481200.
The previous prime is 35124343973. The next prime is 35124344029. The reversal of 35124344013 is 31044342153.
35124344013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 35124344013 - 212 = 35124339917 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35124344713) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 532186998 + ... + 532187063.
It is an arithmetic number, because the mean of its divisors is an integer number (6386244372).
Almost surely, 235124344013 is an apocalyptic number.
35124344013 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
35124344013 is a deficient number, since it is larger than the sum of its proper divisors (15965610963).
35124344013 is a wasteful number, since it uses less digits than its factorization.
35124344013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064374075.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 35124344013 its reverse (31044342153), we get a palindrome (66168686166).
The spelling of 35124344013 in words is "thirty-five billion, one hundred twenty-four million, three hundred forty-four thousand, thirteen".
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