352604743 has 4 divisors (see below), whose sum is σ = 367935408. Its totient is φ = 337274080.

The previous prime is 352604731. The next prime is 352604753. The reversal of 352604743 is 347406253.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 347406253 = 421 ⋅825193.

It is a cyclic number.

It is not a de Polignac number, because 352604743 - 2⁵ = 352604711 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 352604699 and 352604708.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (352604753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7665298 + ... + 7665343.

It is an arithmetic number, because the mean of its divisors is an integer number (91983852).

Almost surely, 2^352604743 is an apocalyptic number.

352604743 is a deficient number, since it is larger than the sum of its proper divisors (15330665).

352604743 is a wasteful number, since it uses less digits than its factorization.

352604743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15330664.

The product of its (nonzero) digits is 60480, while the sum is 34.

The square root of 352604743 is about 18777.7725782373. The cubic root of 352604743 is about 706.4737829702.

The spelling of 352604743 in words is "three hundred fifty-two million, six hundred four thousand, seven hundred forty-three".