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3531430341349 is a prime number
BaseRepresentation
bin110011011000111001101…
…001101010101011100101
3110111121020110012202112021
4303120321221222223211
5430324332131410344
611302152224023141
7513065064424621
oct63307151525345
913447213182467
103531430341349
1111417423aa899
124904b8a61ab1
131c80214859a1
14c2cca4d4181
1561cd983ab84
hex33639a6aae5

3531430341349 has 2 divisors, whose sum is σ = 3531430341350. Its totient is φ = 3531430341348.

The previous prime is 3531430341347. The next prime is 3531430341407. The reversal of 3531430341349 is 9431430341353.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2420535421249 + 1110894920100 = 1555807^2 + 1053990^2 .

It is an emirp because it is prime and its reverse (9431430341353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3531430341349 - 21 = 3531430341347 is a prime.

Together with 3531430341347, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3531430341347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1765715170674 + 1765715170675.

It is an arithmetic number, because the mean of its divisors is an integer number (1765715170675).

Almost surely, 23531430341349 is an apocalyptic number.

It is an amenable number.

3531430341349 is a deficient number, since it is larger than the sum of its proper divisors (1).

3531430341349 is an equidigital number, since it uses as much as digits as its factorization.

3531430341349 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 43.

The spelling of 3531430341349 in words is "three trillion, five hundred thirty-one billion, four hundred thirty million, three hundred forty-one thousand, three hundred forty-nine".