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354049111 = 13257105971
BaseRepresentation
bin10101000110100…
…101110001010111
3220200012120002001
4111012211301113
51211114032421
655044300131
711526240103
oct2506456127
9820176061
10354049111
11171940379
129a6a1647
1358473220
1435042903
1521138691
hex151a5c57

354049111 has 8 divisors (see below), whose sum is σ = 382770864. Its totient is φ = 325539840.

The previous prime is 354049079. The next prime is 354049117. The reversal of 354049111 is 111940453.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 354049111 - 25 = 354049079 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 354049111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (354049117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49645 + ... + 56326.

It is an arithmetic number, because the mean of its divisors is an integer number (47846358).

Almost surely, 2354049111 is an apocalyptic number.

354049111 is a deficient number, since it is larger than the sum of its proper divisors (28721753).

354049111 is a wasteful number, since it uses less digits than its factorization.

354049111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106241.

The product of its (nonzero) digits is 2160, while the sum is 28.

The square root of 354049111 is about 18816.1927870651. The cubic root of 354049111 is about 707.4371071214.

Adding to 354049111 its reverse (111940453), we get a palindrome (465989564).

The spelling of 354049111 in words is "three hundred fifty-four million, forty-nine thousand, one hundred eleven".

Divisors: 1 13 257 3341 105971 1377623 27234547 354049111