3542051113 has 8 divisors (see below), whose sum is σ = 3580769160. Its totient is φ = 3503404800.

The previous prime is 3542051101. The next prime is 3542051143. The reversal of 3542051113 is 3111502453.

It is a happy number.

3542051113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 672520489 + 2869530624 = 25933^2 + 53568^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3542051113 - 2⁵ = 3542051081 is a prime.

It is a super-3 number, since 3×3542051113³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (3542051143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84531 + ... + 119287.

It is an arithmetic number, because the mean of its divisors is an integer number (447596145).

Almost surely, 2^3542051113 is an apocalyptic number.

It is an amenable number.

3542051113 is a deficient number, since it is larger than the sum of its proper divisors (38718047).

3542051113 is a wasteful number, since it uses less digits than its factorization.

3542051113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35867.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 3542051113 is about 59515.1334788052. The cubic root of 3542051113 is about 1524.3508641723.

Adding to 3542051113 its reverse (3111502453), we get a palindrome (6653553566).

The spelling of 3542051113 in words is "three billion, five hundred forty-two million, fifty-one thousand, one hundred thirteen".