3542512045 has 4 divisors (see below), whose sum is σ = 4251014460. Its totient is φ = 2834009632.

The previous prime is 3542512021. The next prime is 3542512067. The reversal of 3542512045 is 5402152453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 405055876 + 3137456169 = 20126^2 + 56013^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3542512045 is a prime.

It is a super-3 number, since 3×3542512045³ (a number of 30 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3542511998 and 3542512016.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 354251200 + ... + 354251209.

It is an arithmetic number, because the mean of its divisors is an integer number (1062753615).

Almost surely, 2^3542512045 is an apocalyptic number.

It is an amenable number.

3542512045 is a deficient number, since it is larger than the sum of its proper divisors (708502415).

3542512045 is an equidigital number, since it uses as much as digits as its factorization.

3542512045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 708502414.

The product of its (nonzero) digits is 24000, while the sum is 31.

The square root of 3542512045 is about 59519.0057460640. The cubic root of 3542512045 is about 1524.4169832650.

Adding to 3542512045 its reverse (5402152453), we get a palindrome (8944664498).

The spelling of 3542512045 in words is "three billion, five hundred forty-two million, five hundred twelve thousand, forty-five".