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35425503413 is a prime number
BaseRepresentation
bin100000111111100001…
…100100100010110101
310101102212100000212222
4200333201210202311
51040022412102123
624135123252125
72362606545026
oct407741444265
9111385300788
1035425503413
1114029856053
126a47b1a045
133457424651
141a00c2cc4d
15dc50d06c8
hex83f8648b5

35425503413 has 2 divisors, whose sum is σ = 35425503414. Its totient is φ = 35425503412.

The previous prime is 35425503409. The next prime is 35425503457. The reversal of 35425503413 is 31430552453.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20044046929 + 15381456484 = 141577^2 + 124022^2 .

It is an emirp because it is prime and its reverse (31430552453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35425503413 - 22 = 35425503409 is a prime.

It is a super-3 number, since 3×354255034133 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35425503473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712751706 + 17712751707.

It is an arithmetic number, because the mean of its divisors is an integer number (17712751707).

Almost surely, 235425503413 is an apocalyptic number.

It is an amenable number.

35425503413 is a deficient number, since it is larger than the sum of its proper divisors (1).

35425503413 is an equidigital number, since it uses as much as digits as its factorization.

35425503413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 35.

The spelling of 35425503413 in words is "thirty-five billion, four hundred twenty-five million, five hundred three thousand, four hundred thirteen".