Base | Representation |
---|---|
bin | 110011101010010100111… |
… | …010011000101101011111 |
3 | 110120101112110012221221201 |
4 | 303222110322120231133 |
5 | 431131142134220111 |
6 | 11314525025140331 |
7 | 514326545215105 |
oct | 63522472305537 |
9 | 13511473187851 |
10 | 3550141320031 |
11 | 1149674250039 |
12 | 49405b18a6a7 |
13 | 1c9a13a9a7c7 |
14 | c3b83515c75 |
15 | 625323346c1 |
hex | 33a94e98b5f |
3550141320031 has 2 divisors, whose sum is σ = 3550141320032. Its totient is φ = 3550141320030.
The previous prime is 3550141320029. The next prime is 3550141320067. The reversal of 3550141320031 is 1300231410553.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3550141320031 - 21 = 3550141320029 is a prime.
It is a super-2 number, since 2×35501413200312 (a number of 26 digits) contains 22 as substring.
Together with 3550141320029, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3550141300031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1775070660015 + 1775070660016.
It is an arithmetic number, because the mean of its divisors is an integer number (1775070660016).
Almost surely, 23550141320031 is an apocalyptic number.
3550141320031 is a deficient number, since it is larger than the sum of its proper divisors (1).
3550141320031 is an equidigital number, since it uses as much as digits as its factorization.
3550141320031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 3550141320031 its reverse (1300231410553), we get a palindrome (4850372730584).
The spelling of 3550141320031 in words is "three trillion, five hundred fifty billion, one hundred forty-one million, three hundred twenty thousand, thirty-one".
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