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36541884437 is a prime number
BaseRepresentation
bin100010000010000100…
…001110100000010101
310111022200000001202022
4202002010032200111
51044314210300222
624442003222525
72432353615142
oct420204164025
9114280001668
1036541884437
1114551a396a3
1270b9977a45
1335a47bc436
141aa91d33c9
15e3d100042
hex88210e815

36541884437 has 2 divisors, whose sum is σ = 36541884438. Its totient is φ = 36541884436.

The previous prime is 36541884367. The next prime is 36541884439. The reversal of 36541884437 is 73448814563.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22391830321 + 14150054116 = 149639^2 + 118954^2 .

It is an emirp because it is prime and its reverse (73448814563) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 36541884437 - 224 = 36525107221 is a prime.

Together with 36541884439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (36541884439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18270942218 + 18270942219.

It is an arithmetic number, because the mean of its divisors is an integer number (18270942219).

Almost surely, 236541884437 is an apocalyptic number.

It is an amenable number.

36541884437 is a deficient number, since it is larger than the sum of its proper divisors (1).

36541884437 is an equidigital number, since it uses as much as digits as its factorization.

36541884437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7741440, while the sum is 53.

The spelling of 36541884437 in words is "thirty-six billion, five hundred forty-one million, eight hundred eighty-four thousand, four hundred thirty-seven".