Base | Representation |
---|---|
bin | 110101100011011001101… |
… | …011011010000010000111 |
3 | 111000211002120021101202202 |
4 | 311203121223122002013 |
5 | 440243413333240241 |
6 | 11454345042425115 |
7 | 526611254131442 |
oct | 65433153320207 |
9 | 14024076241682 |
10 | 3680144040071 |
11 | 1199816407834 |
12 | 4b52a096219b |
13 | 2090613b5415 |
14 | ca1970cc659 |
15 | 65ae0533d9b |
hex | 358d9ada087 |
3680144040071 has 2 divisors, whose sum is σ = 3680144040072. Its totient is φ = 3680144040070.
The previous prime is 3680144040059. The next prime is 3680144040073. The reversal of 3680144040071 is 1700404410863.
It is a happy number.
3680144040071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3680144040071 is a prime.
Together with 3680144040073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3680144040073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1840072020035 + 1840072020036.
It is an arithmetic number, because the mean of its divisors is an integer number (1840072020036).
Almost surely, 23680144040071 is an apocalyptic number.
3680144040071 is a deficient number, since it is larger than the sum of its proper divisors (1).
3680144040071 is an equidigital number, since it uses as much as digits as its factorization.
3680144040071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 38.
The spelling of 3680144040071 in words is "three trillion, six hundred eighty billion, one hundred forty-four million, forty thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •