Base | Representation |
---|---|
bin | 111001001111111011111… |
… | …001100011111011101101 |
3 | 111221002122200012021100210 |
4 | 321033323321203323231 |
5 | 1003424040014341240 |
6 | 12211151011413033 |
7 | 554142122562165 |
oct | 71177371437355 |
9 | 14832580167323 |
10 | 3934121246445 |
11 | 12874a6976aa5 |
12 | 5365612b4179 |
13 | 226ca8444b60 |
14 | d85abbdd5a5 |
15 | 6c5075be780 |
hex | 393fbe63eed |
3934121246445 has 32 divisors (see below), whose sum is σ = 6787563253632. Its totient is φ = 1934292517632.
The previous prime is 3934121246359. The next prime is 3934121246477. The reversal of 3934121246445 is 5446421214393.
3934121246445 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3934121246445 - 213 = 3934121238253 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3934121246394 and 3934121246403.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12899059 + ... + 13200528.
It is an arithmetic number, because the mean of its divisors is an integer number (212111351676).
Almost surely, 23934121246445 is an apocalyptic number.
It is an amenable number.
3934121246445 is a deficient number, since it is larger than the sum of its proper divisors (2853442007187).
3934121246445 is a wasteful number, since it uses less digits than its factorization.
3934121246445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26100381.
The product of its digits is 2488320, while the sum is 48.
The spelling of 3934121246445 in words is "three trillion, nine hundred thirty-four billion, one hundred twenty-one million, two hundred forty-six thousand, four hundred forty-five".
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