Base | Representation |
---|---|
bin | 111001010111100101010… |
… | …000001101011000101001 |
3 | 111221212211211202021001011 |
4 | 321113211100031120221 |
5 | 1004042343244221100 |
6 | 12215025412223521 |
7 | 554552433440311 |
oct | 71274520153051 |
9 | 14855754667034 |
10 | 3942331242025 |
11 | 128aa2a234210 |
12 | 53807290aba1 |
13 | 2279b6331ac7 |
14 | d8b4a32c441 |
15 | 6c83824abba |
hex | 395e540d629 |
3942331242025 has 24 divisors (see below), whose sum is σ = 5564764171584. Its totient is φ = 2742491294400.
The previous prime is 3942331242023. The next prime is 3942331242029. The reversal of 3942331242025 is 5202421332493.
It is not a de Polignac number, because 3942331242025 - 21 = 3942331242023 is a prime.
It is a super-2 number, since 2×39423312420252 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3942331242023) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 311640414 + ... + 311653063.
It is an arithmetic number, because the mean of its divisors is an integer number (231865173816).
Almost surely, 23942331242025 is an apocalyptic number.
It is an amenable number.
3942331242025 is a deficient number, since it is larger than the sum of its proper divisors (1622432929559).
3942331242025 is a wasteful number, since it uses less digits than its factorization.
3942331242025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 623293521 (or 623293516 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 3942331242025 in words is "three trillion, nine hundred forty-two billion, three hundred thirty-one million, two hundred forty-two thousand, twenty-five".
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