3971244775680 has 1440 divisors, whose sum is σ = 17553894107904. Its totient is φ = 834785574912.

The previous prime is 3971244775679. The next prime is 3971244775711. The reversal of 3971244775680 is 865774421793.

3971244775680 is a `hidden beast` number, since 3 + 9 + 7 + 1 + 24 + 47 + 7 + 568 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1440).

It is a super-3 number, since 3×3971244775680³ (a number of 39 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 3273902754 + ... + 3273903966.

It is a 2-persistent number, because it is pandigital, and so is 2⋅3971244775680 = 7942489551360, but 3⋅3971244775680 = 11913734327040 is not.

Almost surely, 2^{3971244775680} is an apocalyptic number.

3971244775680 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3971244775680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (8776947053952).

3971244775680 is an abundant number, since it is smaller than the sum of its proper divisors (13582649332224).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3971244775680 is a wasteful number, since it uses less digits than its factorization.

3971244775680 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1613 (or 1590 counting only the distinct ones).

The product of its (nonzero) digits is 71124480, while the sum is 63.

The spelling of 3971244775680 in words is "three trillion, nine hundred seventy-one billion, two hundred forty-four million, seven hundred seventy-five thousand, six hundred eighty".