Base | Representation |
---|---|
bin | 101101011110011111001110… |
… | …0111100111011110101110011 |
3 | 1221110100000010011121110102211 |
4 | 1122330332130330323311303 |
5 | 404412314004024114103 |
6 | 3534432030101152551 |
7 | 150154042016505211 |
oct | 13274763474736563 |
9 | 1843300104543384 |
10 | 400014412332403 |
11 | 106503183453310 |
12 | 38a455813bb757 |
13 | 142282743c85ab |
14 | 70acb2d7b5cb1 |
15 | 313a45d55e36d |
hex | 16bcf9cf3bd73 |
400014412332403 has 4 divisors (see below), whose sum is σ = 436379358908088. Its totient is φ = 363649465756720.
The previous prime is 400014412332373. The next prime is 400014412332449. The reversal of 400014412332403 is 304233214410004.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 400014412332403 - 217 = 400014412201331 is a prime.
It is a super-4 number, since 4×4000144123324034 (a number of 60 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (400014412372403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18182473287826 + ... + 18182473287847.
It is an arithmetic number, because the mean of its divisors is an integer number (109094839727022).
Almost surely, 2400014412332403 is an apocalyptic number.
400014412332403 is a deficient number, since it is larger than the sum of its proper divisors (36364946575685).
400014412332403 is a wasteful number, since it uses less digits than its factorization.
400014412332403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36364946575684.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 400014412332403 its reverse (304233214410004), we get a palindrome (704247626742407).
The spelling of 400014412332403 in words is "four hundred trillion, fourteen billion, four hundred twelve million, three hundred thirty-two thousand, four hundred three".
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